What do I do? Take y' of the first equation and then set it equal to the slope of the second equation and solve for x? answer is A.

This is what I got:

$\displaystyle

y1'=2-4x^{-2}$

$\displaystyle y2=-2x+6$

$\displaystyle 2-4x^{-2}=-2x+6$

$\displaystyle 2(2x^{-2}-x+2)$

Did I take the wrong route/ what would I do next?