Suppose f(2) = 3 and f'(2) = 1; Find f(-2) and f'(-2), assuming that f(x) is:
My friend and I reasoned purely through our own logic that a) Even would be:
f(-2) = 3
f'(-2) = 1
Because even functions are typically parabolas and therefore they have mirrored points.
I'm not sure if that's actually right, and I don't know what to do for b) Odd.