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Thread: [SOLVED] Integration

  1. December 11th 2009, 07:04 PM #1
    nameck
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    [SOLVED] Integration

    \int{\left(\frac{x}{x^2 + 1}\right)\,dx}
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  2. December 11th 2009, 07:43 PM #2
    VonNemo19
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    Quote Originally Posted by nameck View Post
    \int{\left(\frac{x}{x^2 + 1}\right)\,dx}
    I responded to your other post.
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  3. December 11th 2009, 08:23 PM #3
    millerst
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    <br /> <br /> \int{\left(\frac{x}{x^2 + 1}\right)\,dx}<br />

    <br /> u=x^2 + 1<br />
    du=2xdx

    <br /> <br /> = 0.5\int{\left(\frac{1}{u}\right)\,du}<br />

    = <br /> 0.5(Ln|x^2+1|) + C<br />
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