Quote:

"

Factored out a c and got:

"

add sin to both sides

Sin(Ct)=root3 Cos(Ct)

now square both sides

sin^2(Ct)=3Cos(Ct)

pythagorean identity

1-cos^2(Ct)=3Cos(Ct)

get on one side

cos^2(Ct)+3Cos(Ct)-1=0

use quadratic formula to find cos(Ct)

one of the answers is -3.3ish which isn't possible

for cos and the other is .30277 which is possible for cos

so use that one.

arccos(.30277) = 1.26 radians

t=1.26/C

just plug that answer back in to make sure i didn't screw up. Im pretty high right now so who knows? When ever you're doing trig stuff and theres sines and cosines all over the place, it helps to get all sines or all cosines with the help of identities. Practice makes perfect so don't stop hammering those problems.