Calculate the area under the graph of f(x) = 3x^2 and above the x-axis on the interval from x= -2 to x= 2.

I entered this graph into my calculator and there is no area under the graph, so I assumed it was 0. Then, I did fnInt(3x^2,x,-2,2) and got 16 as my solution. Just was wondering if I could get a second opinion to see if I did this right.