velocity in m/s is : v(t) = 3t^1/2 +3 find the average velocity between t = 5 and t = 8
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Originally Posted by B-lap velocity in m/s is : v(t) = 3t^1/2 +3 find the average velocity between t = 5 and t = 8 Apply the definition of the average value of a function over an interval: $\displaystyle \frac{1}{8 - 5} \int_5^8 v(t) \, dt$.
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