Any help you could give would be wonderful! Thanks!
The circle is revolved about the line thus generating a torus (doughnut). Find its surface area.
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We are in the same class.
2∏a (2∏b-0)= 4∏^2ab
How did you get the answer? Can you give me specifics? Thanks!
The formula for the surface area of a torus is A=4π^2ab, where b is the radius of the tube and a is the distance from the center of the tube to the center of the torus.
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