...Revenue for sales of rubber baby-buggy bumpers is given by
R(q)=90q^2-q^3 for 0<q<70 .
a.what is the maximum revenue?
b.at what quantity is revenue increasing the fastest?
I tried finding R'(q)=180q-3q^2
and then from here found out p=-b/2a so that price(p) is set in R'(p) to find the maximum revenue.
180q - 3q^2 = 0
3q(60 - q) = 0
q = 0 , q = 60 ... which value of q maximizes R ?
once you determine that fact, find R(q) for that value.
I am not quite sure what part b wants.Am I doing part a correct?Any help?
the question is asking for the value of q for which R'(q) is a maximum ...
R''(q) = 180 - 6q = 0
q = 30 ... will this value of q yield a maximum for R'(q) ?
how can you tell?