x[0,1] f(x)=sinx/1+x^2 isn't 1+x^2 arctan? I wasn't sure how to approach this problem, I know sin/cos = tan, so would i use 1/2 x dx/1+x^2? I have no clue haha. Help please.
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As written, the integrand is as follows: I have a feeling you mean one of the following...? Please confirm or correct. Thank you!
Originally Posted by stapel As written, the integrand is as follows: I have a feeling you mean one of the following...? Please confirm or correct. Thank you! I meant a
so I guess no one understands this.
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