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Math Help - Could i Have help with a problem i am stuck on please.

  1. #1
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    Could i Have help with a problem i am stuck on please.

    Hello, I have a small problem that i am having trouble with,

    Find the co-ordinates of the point on the curve y=sqrt(x) which is closest to the point (5/2,0)

    I already know a little about the process, I know the formula to find distance from the origin is sqrt(x^2+y^2) and I substitute sqrt(x) for y,
    But then I simplify it down and get sqrt(-4x).
    If i could have some pointers i would be really greatfull.
    Thank you.
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  2. #2
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    Quote Originally Posted by paddy12321 View Post
    Hello, I have a small problem that i am having trouble with,

    Find the co-ordinates of the point on the curve y=sqrt(x) which is closest to the point (5/2,0)

    I already know a little about the process, I know the formula to find distance from the origin is sqrt(x^2+y^2) and I substitute sqrt(x) for y,
    But then I simplify it down and get sqrt(-4x).
    If i could have some pointers i would be really greatfull.
    Thank you.
    This distance between two points is given by

    d=\sqrt{(x_1-x_0)^2+(y_1-y_0)^2}

    So the distance between the point and the function is

    d=\sqrt{\left(\frac{5}{2}-x \right)^2+(0-\sqrt{x})^2}

    Note that minimizing the square of the distance will also solve the problem

    I hope this helps
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