A force of 4 pounds is required to hold a spring stretched 0.3 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.9 feet beyond its natural length?

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- Dec 10th 2009, 09:13 AMderekjonathonForce to hold a spring
A force of 4 pounds is required to hold a spring stretched 0.3 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.9 feet beyond its natural length?

- Dec 10th 2009, 11:48 AMskeeter
- Dec 10th 2009, 11:57 AMnovice
First you must find the spring constant, , using .

You are given feet, and lbs.

.

The negative sign indicates that the spring is in tension.

You are also give feet, which is how much the spring is stretched beyond its natural length.

Work =

The negative sign indicates work exerted against the sprink energy.