The Maclaurin series for sin x is

use the corresponding Maclaurin polynomial of degree 5 to approximate

integration from -1 to 1

i dont have any idea to solve it..

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- Dec 10th 2009, 03:03 AMnameckMaclaurin Series(approximation)
The Maclaurin series for sin x is

use the corresponding Maclaurin polynomial of degree 5 to approximate

integration from -1 to 1

i dont have any idea to solve it..

- Dec 10th 2009, 03:35 AMHallsofIvy
- Dec 10th 2009, 04:04 AMnameck
got it!! =)

- Dec 10th 2009, 04:19 AMchisigma
The McLaurin expasion of the sin function is...

(1)

Only the 'odd' powers of x give contribution, so that is...

(2)

... no matter which is a...

http://digilander.libero.it/luposabatini/notte1.jpg

Merry Christmas from Italy

- Dec 10th 2009, 04:44 AMHallsofIvy
- Dec 10th 2009, 04:57 AMchisigma
I have posted that in order to clarify the misundestanding caused by the fact that the function to be integrated is and not as written is the first post by nameck: the Maclaurin series for

__sin x__is...

http://digilander.libero.it/luposabatini/notte1.jpg

Merry Christmas from Italy

- Dec 10th 2009, 05:00 AMnameck
i got 1.8922222..

is my answer correct?