hey there.. i hope u guys can help me..

the question is...

Determine the interval and radius of convergence of the power series below..

$\displaystyle \sum\limits_{k=0}^\infty$k!(x-3)^k

i've already find the radius, r = 0

then..

c - r < x < c + r

3 - 0 < x < 3 + 0

hence, x = 3

when x = 3..

$\displaystyle \sum\limits_{k=0}^\infty$k!(3-3)^k = 0

so.. the interval of convergence is 0..

am i do it right?