# Math Help - Final tomorrow.. Limit help needed asap

1. ## Final tomorrow.. Limit help needed asap

(e^(2x)-1)/(e^x-1) as x approaches 0

2. Originally Posted by ihatemath
(e^(2x)-1)/(e^x-1) as x approaches 0
$\frac{e^{2x} - 1}{e^x - 1} = \frac{(e^x + 1)(e^x - 1)}{e^x - 1}$

$= e^x + 1$.

So what do you think this tends to as $x \to 0$?

3. oh my gosh! I can't believe I missed something so simple! Thanks!

4. $lim_{x \rightarrow 0} ~\frac{e^{2x} - 1}{e^x - 1} = lim_{x \rightarrow 0} ~\frac{(e^x - 1)(e^x + 1)}{e^x - 1} = lim_{x \rightarrow 0} ~(e^x + 1) = 2$

5. Originally Posted by dedust
$lim_{x \rightarrow 0} ~\frac{e^{2x} - 1}{e^x - 1} = lim_{x \rightarrow 0} ~\frac{(e^x - 1)(e^x + 1)}{e^x - 1} = lim_{x \rightarrow 0} ~(e^x + 1) = 2$
You're a little late...

6. Originally Posted by Prove It
You're a little late...
yeah,..still newbie in LaTex

7. Don't you hate it when someone posts while you are writing a response?