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Math Help - Final tomorrow.. Limit help needed asap

  1. #1
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    Final tomorrow.. Limit help needed asap

    (e^(2x)-1)/(e^x-1) as x approaches 0
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  2. #2
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    Quote Originally Posted by ihatemath View Post
    (e^(2x)-1)/(e^x-1) as x approaches 0
    \frac{e^{2x} - 1}{e^x - 1} = \frac{(e^x + 1)(e^x - 1)}{e^x - 1}

     = e^x + 1.


    So what do you think this tends to as x \to 0?
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  3. #3
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    oh my gosh! I can't believe I missed something so simple! Thanks!
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  4. #4
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    lim_{x \rightarrow 0} ~\frac{e^{2x} - 1}{e^x - 1} = lim_{x \rightarrow 0} ~\frac{(e^x - 1)(e^x + 1)}{e^x - 1} = lim_{x \rightarrow 0} ~(e^x + 1) = 2
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  5. #5
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    Quote Originally Posted by dedust View Post
    lim_{x \rightarrow 0} ~\frac{e^{2x} - 1}{e^x - 1} = lim_{x \rightarrow 0} ~\frac{(e^x - 1)(e^x + 1)}{e^x - 1} = lim_{x \rightarrow 0} ~(e^x + 1) = 2
    You're a little late...
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  6. #6
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    Quote Originally Posted by Prove It View Post
    You're a little late...
    yeah,..still newbie in LaTex
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  7. #7
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    Don't you hate it when someone posts while you are writing a response?
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