Edit: Title should read double integral... oops
Having a little trouble figuring this one out.
Region bounded by 4x^2 + y^2 = 4z and z = 2
Thanks.
The equation that bounds the region of integration can be rewritten
$\displaystyle \left(\frac{x}{\sqrt{2}}\right)^2+\left(\frac{y}{2 \sqrt{2}}\right)^2=1.$
This defines an ellipse whose equation in polar coordinates is
$\displaystyle r=\sqrt{2}\cos\theta + 2\sqrt{2}\sin\theta.$