For reference, the formula for surface area is
I'm so stuck with the Parametric Surface Area problem right now T_T
Can anyone please help me out?
There are two questions in total, if you can help me with any one of the two, it'll be so appreciated!
Question 1:
The part of the plane 3x+2y+z = 6 that lies in the 1st octant.
Question 2:
The surface z = 2/3 (x^(3/2) + y^(3/2)), 0 <= x <= 1, 0 <= y <= 1
Please, help!
The plane 3x+ 2y+ z= 6 crosses the xy-plane, where z= 0, in the line 3x+ 2y= 6. That, in turn, has y-intercept (0, 3) and x-intercept (2, 0). You can take the limits of integration to be x=0 to 2 and, for each x, y= 0 to 3- (3/2)x. Or, if you prefer to integrate with respect to x first, y from 0 to 3 and, for each y, x from 0 to 2- (2/3)y.
Question 2:
The surface z = 2/3 (x^(3/2) + y^(3/2)), 0 <= x <= 1, 0 <= y <= 1
Please, help!