Why is it Ax(x+3) + B(x+3) + Cx^2 instead of Ax^2(x+3) + Bx(x+3) + Cx^3
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Originally Posted by swatpup32 Why is it Ax(x+3) + B(x+3) + Cx^2 instead of Ax^2(x+3) + Bx(x+3) + Cx^3 hello $\displaystyle \frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+3}=\frac{Ax(x +3)+B(x+3)+Cx^2}{x^2(x+3)}$
I'm sorry, but I still don't understand.
Originally Posted by swatpup32 I'm sorry, but I still don't understand. do you know how to make a single fraction of this expression, $\displaystyle \frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+3}$ ?
okay, I wasn't thinking about it as a fraction. I was only considering the numerator. An, x canceled out from the numerator and denominator.
Originally Posted by Raoh do you know how to make a single fraction of this expression, $\displaystyle \frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+3}$ ? you must make $\displaystyle \frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+3}$ a single fraction with the denominator $\displaystyle x^2(x+3)$.
$\displaystyle \frac{x^2+8x-3}{x^2(x+3)}$$\displaystyle =\frac{Ax(x+3)+B(x+3)+Cx^2}{x^2(x+3)}$ now get rid of the same denominators and you'll have, $\displaystyle x^2+8x-3=Ax(x+3)+B(x+3)+Cx^2$
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