Use L'Hospital's Rule to find the following limit: I am not sure how to use L'Hospital's rule for this. I know that the and so therefore, Can someone help me solve this using L'Hospital's Rule. Thank you.
Last edited by mybrohshi5; Dec 9th 2009 at 03:56 PM.
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Originally Posted by mybrohshi5 Use L'Hospital's Rule to find the following limit: I am not sure how to use L'Hospital's rule for this. I know that the and so therefore, Can someone help me solve this using L'Hospital's Rule. Thank you. (by the Hospital's rule). therefore
That's wrong, Raoh :P , but What you need to do here: Set , evaluate and take the limit as x goes to infinity. (Hint: the answer is not 1)
Originally Posted by Defunkt That's wrong, Raoh :P , but What you need to do here: Set , evaluate and take the limit as x goes to infinity. (Hint: the answer is not 1) errr ! . hope it's right now
Im not exactly sure how by setting t equal to the function then taking the natural log of it is using L'Hospitals Rule? Could you maybe show me in a little more detail what you mean. Thank you
Originally Posted by Raoh errr ! . hope it's right now Could you show me how Im not really understanding how it equals two
Originally Posted by mybrohshi5 Could you show me how Im not really understanding how it equals two put when we will have . therefore we should evaluate, now use the hospital's rule. you'll get, hope that right.
Last edited by Raoh; Dec 9th 2009 at 03:33 PM.
When i graph the equation it looks like it is approaching about 7.4 when x goes to infinity????
Originally Posted by mybrohshi5 When i graph the equation it looks like it is approaching about 7.4 when x goes to infinity???? that's because the limit is
Could you please show me how to use L'Hospital's Rule to show that it is e^2 cause Naoh tried it and came up with 2
He came up with Now use the fact that to conclude the result.. (remember - you're looking for t)
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