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Math Help - Find the derivative of this Function.

  1. #1
    Junior Member Cyberman86's Avatar
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    Question Find the derivative of this Function.

    I don't really know how to do this one, can someone please help me step by step, Thanks.

    y=e^(cos+lnt)

    = d/dx(e) + d/dx(cos+lnt)
    = e + (-sin+lnt)
    = e-sint
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by Cyberman86 View Post
    I don't really know how to do this one, can someone please help me step by step, Thanks.

    y=e^(cos+lnt)

    = d/dx(e) + d/dx(cos+lnt)
    = e + (-sin+lnt)
    = e-sint
    Your equation makes no sense. cos of what? Is lnt = ln(t)?
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  3. #3
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    Smile

    hello
    \left (\exp(u)  \right )'=u'\times\exp(u)
    put u=\cos(t)+\log(t)
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  4. #4
    Junior Member Cyberman86's Avatar
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    Quote Originally Posted by e^(i*pi) View Post
    Your equation makes no sense. cos of what? Is lnt = ln(t)?
    That's how its written in the book.

    y=e^(cos+lnt)
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  5. #5
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    Quote Originally Posted by Cyberman86 View Post
    That's how its written in the book.

    y=e^(cos+lnt)
    there must be a typo
    i think you meant (they meant) y=\exp(\cos(t)+\ln(t))<br />
=t\times \exp(\cos(t)),in this case the derivative is,
    y'=\exp(\cos(t))-t\times\sin(t)\times\exp(\cos(t)).
    hope that helps.
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