I don't really know how to do this one, can someone please help me step by step, Thanks. y=e^(cos+lnt) = d/dx(e) + d/dx(cos+lnt) = e + (-sin+lnt) = e-sint
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Originally Posted by Cyberman86 I don't really know how to do this one, can someone please help me step by step, Thanks. y=e^(cos+lnt) = d/dx(e) + d/dx(cos+lnt) = e + (-sin+lnt) = e-sint Your equation makes no sense. cos of what? Is lnt = ln(t)?
hello $\displaystyle \left (\exp(u) \right )'=u'\times\exp(u)$ put $\displaystyle u=\cos(t)+\log(t)$
Originally Posted by e^(i*pi) Your equation makes no sense. cos of what? Is lnt = ln(t)? That's how its written in the book. y=e^(cos+lnt)
Originally Posted by Cyberman86 That's how its written in the book. y=e^(cos+lnt) there must be a typo i think you meant (they meant) $\displaystyle y=\exp(\cos(t)+\ln(t)) =t\times \exp(\cos(t))$,in this case the derivative is, $\displaystyle y'=\exp(\cos(t))-t\times\sin(t)\times\exp(\cos(t))$. hope that helps.
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