1. ## Evaluate the integral

Evaluate:

$\int ^1_0 \frac {d}{dx} (e^{arctan(x)}) dx$

This problem does not make sense to me?

I am reading it as find the derivative $(\frac {d}{dx})$ of the antiderivative? .... which does not make sense to me at all.

I guess im just unsure how to do this problem in general.

Any help would be great.

Thank you.

2. Originally Posted by mybrohshi5
Evaluate:

$\int ^1_0 \frac {d}{dx} (e^{arctan(x)}) dx$

This problem does not make sense to me?

I am reading it as find the derivative $(\frac {d}{dx})$ of the antiderivative? .... which does not make sense to me at all.

I guess im just unsure how to do this problem in general.

Any help would be great.

Thank you.
Surely the antiderivative of a derivative is the original function...

So $\int_0^1{\frac{d}{dx}\left(e^{\arctan{x}}\right)\, dx} = \left[e^{\arctan{x}}\right]_0^1$.

3. Originally Posted by mybrohshi5
Evaluate:

$\int ^1_0 \frac {d}{dx} (e^{arctan(x)}) dx$

This problem does not make sense to me?

I am reading it as find the derivative $(\frac {d}{dx})$ of the antiderivative? .... which does not make sense to me at all.

I guess im just unsure how to do this problem in general.

Any help would be great.

Thank you.
The integral

$\int_a^b\frac{d}{dx}f(x)dx=f(b)-f(a)$...

Think about it. You take the derivative of a function, then integrate the function, leaving you with the original function. I think the point to the excersie is to show that differentiation and integration are inverse processes.

4. Thank you. that does make sense i was not thinking straight at that moment haha.

how would i go about doing

$\frac {d}{dx} \int ^1_0 e^{arctan(x)} dx$

Thank you. This is helping me understand a lot for my final exam coming up =)

5. Would i evaluate the integral first and then take the derivative of that number?

if so the derivative of a number is just 0 so is that the answer to this second one?

just zero?

6. Originally Posted by mybrohshi5
Would i evaluate the integral first and then take the derivative of that number?

if so the derivative of a number is just 0 so is that the answer to this second one?

just zero?
Yes. In this case, we are dealing with a definite integral. This implies that you are taking the derivative of a constant.