Hi, could someone tell me if this is the correct answer?
$\displaystyle
\int_0^2 {3x^5e^{x^3}dx}
$
I got:
$\displaystyle
7e^8 +1 $
Here is what I did, can you point out where i am going wrong:
$\displaystyle
\int_{e}^{1} \ \frac{(ln(x))^{1/n}}{x} \ dx
$
let ln(x) = u
du = 1/x dx
change limits of integration
x=e then u=1
x=1, u=0
$\displaystyle =\int_{1}^{0} {u}^{1/n}du
$
$\displaystyle = \frac {n{u}^{1/n +1}}{1+n}\
$