axes and a curve which passes through the points (0,14), (h,16), (2h,15), ..., (18h,6).
A=(h/3)[14+4x16+2x15+4x15+ ... +4x6+6]=(h/3)x622,
but as it seems to be keeping the value of h to itself there does not seem to be much more that can be done.
However as we have been told last time this was asked (here) that h is 6 metres the area is:
A = 1244 square metres.