Can you help me please?

Which is the value of this integral?

$\displaystyle

\displaystyle\int_{0}^{\infty}\displaystyle\frac{l nx}{1+x^2}dx

$

Thanks

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- Dec 7th 2009, 05:17 PMosodudValue of this indefinite integral
Can you help me please?

Which is the value of this integral?

$\displaystyle

\displaystyle\int_{0}^{\infty}\displaystyle\frac{l nx}{1+x^2}dx

$

Thanks - Dec 7th 2009, 05:31 PMBruno J.
That's a

*definite*integral.

What is lu(x)? Did you mean ln(x)? - Dec 7th 2009, 06:12 PMKrizalid
it's finite and its value is zero.

put $\displaystyle x=\frac1t.$ - Dec 7th 2009, 06:24 PMosodud
- Dec 7th 2009, 06:51 PMBruno J.