$\displaystyle y = (ln x)^4$

The given answer is $\displaystyle 4/x (ln x)^3$. The problem I'm having is, isn't it one of the rules that an exponent is transferred to the base? I mean, should $\displaystyle (ln x)^4$ become $\displaystyle 4 (ln x)$? The answer used the chain rule right away without modifying the function.