How can I show that:

$\displaystyle \int \frac{sin(x)}{(2-cos(x))^3}dx = -\frac{1}{2(2-cos(x)^2} + c$

I know that the 2nd half of the equation equates to:

$\displaystyle -\frac{1}{2(4-4cos(x)+cos(x)^2)}$

but how do I integrate the first part of the equation?

Thanks.