[SOLVED] Limits

**antisane** · December 7th 2009, 07:29 AM

hey, will appreciate the help with the following:
$ \lim_{x\rightarrow 1}(\frac{\sqrt{x-1}}{x^2-1}) $

Thanks !

**tonio** · December 7th 2009, 07:53 AM

Originally Posted by antisane

hey, will appreciate the help with the following:
$ \lim_{x\rightarrow 1}(\frac{\sqrt{x-1}}{x^2-1}) $
Thanks !

Hints: $x^2-1=(x-1)(x+1)$ and $\frac{\sqrt{a}}{a}=\frac{1}{\sqrt{a}}\,\,\,\forall a>0$ .

This means that the limits is $+\infty$ , when $x\rightarrow 1^+$ , since the function isn't defined for $x\le 1$ .

Tonio

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