# Math Help - [SOLVED] Limits

1. ## [SOLVED] Limits

hey, will appreciate the help with the following:
$

\lim_{x\rightarrow 1}(\frac{\sqrt{x-1}}{x^2-1})
$

Thanks !

2. Originally Posted by antisane
hey, will appreciate the help with the following:
$

\lim_{x\rightarrow 1}(\frac{\sqrt{x-1}}{x^2-1})
$

Thanks !

Hints: $x^2-1=(x-1)(x+1)$ and $\frac{\sqrt{a}}{a}=\frac{1}{\sqrt{a}}\,\,\,\forall a>0$.

This means that the limits is $+\infty$ , when $x\rightarrow 1^+$, since the function isn't defined for $x\le 1$.

Tonio