I'm unsure or not if the anti derivative of this would be displacement, in fact i'm unsure of how to even tackle this. Please help me, I'm clueless!
3. v(t) = t^3 -5t^2 +6t
a) determine displacement over the interval 0-5
b) determine total distance over the interval 0-5
a) So the antiderivative would be displacement assuming I calculated for t=5? that feels too simple but thats the only answer I'm coming up with.
as for example b) i've sketched the graph of velocity (should I be sketching position?) roughly by plugging in values of t, but I don't think I'm getting the right answer as setting the equation equal to 0 provides me with the information that there is negative velocity somewhere in there, can anyone help me with the proper method?