first this has zeros a x=0, and x=2, the latter of multiplicity 3, so we know

that the curve looks like (x-2)^3 close tp x=2, and so we expect this point

to be a point of inflection.

Also as x goes to +/- infinity y goes to +infinity.

Now lets look for the stationary points:

dy/dx= (x-2)^3 + 3 x (x-2)^2 = (x-2)^2 [(x-2) + 3x]=2 (x-1) (2x -1)

Which is equal to zero when x=1/2, and when x=2. Then we can deduce

from shape of the cureve and the position of the zeros of y, that x=1/2 is a

minimum, and x=2 a point of inflection (we could confirm this with the

second derivative test if we wanted).

y~=-1.68, at the minima corresponding to x=1/2.

Putting this all together we get something like the attachment.

RonL