Can someone start me out with this?

(lnx)^2 dx

I thought to make u = lnx, but then du = dx/x... I cant use it with that x, can I?

thanks!

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- December 6th 2009, 04:39 PMMorgan82Integrate
Can someone start me out with this?

(lnx)^2 dx

I thought to make u = lnx, but then du = dx/x... I cant use it with that x, can I?

thanks! - December 6th 2009, 04:42 PMJhevon
See here

- December 6th 2009, 04:45 PMProve It