(cosx)^3 * (sinx)^2 dx
Can someone tell me how to start this, how to get at it? Thanks
True, there's nothing wrong with it.
It's just that if a student is trying to get a function to be of the form $\displaystyle f\left(u(x)\right)\cdot\frac{du}{dx}$, it's hard enough to find the correct product as it is, let alone having a second product in there.