I tried: u=xsinx, du=xcox+sinx v=sinx, dv=cosx but then I got stuck on integrating...
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Originally Posted by genlovesmusic09 I tried: u=xsinx, du=xcox+sinx v=sinx, dv=cosx but then I got stuck on integrating... Recall that 2sinxcosx = sin(2x). So I would recommend that you rewrite the integral as
Originally Posted by genlovesmusic09 I tried: u=xsinx, du=xcox+sinx v=sinx, dv=cosx but then I got stuck on integrating... Another way: Since , We get: From here it should be easy (find the RHS and divide it by 2 to get the answer).
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