you should have ended up with y' = 2x - sin(pi(x^2 + 1)) (2x * pi)
so for you have the slope of he point (1,2) to be m=2 .... now you can find the pint slope form equation
For each of the following, compute and find the equation for the tangent line at the indicated point x0. You may leave your answers in point-slope form
1. ; x0 = 1
for #1.
I found and used the chain rule for the cosine part and ended up with
do i then use the tangent line formula ?
?
if so, how do i plug in the numbers?