at the point (-1,1). We need to find y' ... what do?
Here's what I did, please tell me where I went wrong.
3(x+y)^2 (1+y') = 3x^2 + 3y^2 y'
How do I proceed?
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Keep solving and then you want to isolate the y' in one side and the x and y in the other. Then you'll solve for y'.
Originally Posted by Arturo_026
Keep solving and then you want to isolate the y' in one side and the x and y in the other. Then you'll solve for y'. I got as far as . How do I proceed from there?
Hold on, This is wrong. give me a bit more time to correct it
Look, buddy. How did you go from to ???
EDIT: Nevermind, I'll wait until your edit.
This should be correct.
I apologize for my mistake, if it serves as an excuse, I was solving it in my head because i couldn't find paper.
The problem I was having is that I didn't expand ASAP. Your step by step solution helped me see my mistakes. Thanks for the help, bromosapien. And no worries about the error.
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