You will use the arclength formula
.
Now substitute this into the arclength formula and remember .
I have tried this one over and over and can't get the right answer. Can anyone help?
Consider the parametric equation
x = 16(cosθ+ θsinθ)
y = 16(sinθ− θcosθ)
What is the length of the curve for θ = 0 to θ = [3/10] π?
I have L=sqrt (dx/dt)^2 + (dy/dt)^2
dx/dt = 16t (sin(t)+sin(t)+t cos(t))
dy/dt= 16t (-cos(t)-cos(t)+t sin(t))
Is that right?