∫ (1-x^2) dx from -1 to 1
I know how to solve using the first fundamental theorem, but I don't understand Riemann Sums.
Can anyone help?
A Reimann sum is an illustration of what an integral is. It is the area of an
infinite number of rectangles under the graph. Thus, giving the area.
If we come off of the right side of the rectangles, we can use
Where .
In this case, each subinterval has length
So, we get
Thereby,
Giving the area of rectangle k as
The sum of the area of all these rectangles is
But we know from some identities that
We sub these is and take the limit as n-->infinity. This means the number of rectangles becomes larger and larger and we approach the area under the curve.
Doing all this algebra we get:
Which is the value of the integral
Subdivide the interval [-1,1] in n equal subintervals .
In each subinterval choose the leftmost point to evaluate : , and now
form your Riemann sums with the above (we can CHOOSE as we did since f is continuous in [-1,1] so we already know it is Riemann integrable there and thus the Riemann sums will converge to the integral's value no matter what sundivision of the interval and what points in it we choose):
...
Tonio