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Thread: Optimizations problem with derivatives

  1. #1
    s3a is offline
    Super Member
    Nov 2008

    Optimizations problem with derivatives

    Question: (Attached) 59 b and c (I did a).

    b: About 8.5 inches by 2 inches.
    c: 20/sqrt(3) inches by 20*sqrt(2/3) inches

    My work is also attached for #59 a (Page 12/14 of pdf file) which I did successfully. I cannot complete b to get to c and for b my problem is that, I cannot find a relationship between the two variables to differentiate a function with one variable. As for #59 b, I thought I was on to something and wrote some unnecessary (I think) things.

    Any help would be greatly appreciated!
    Thanks in advance!
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  2. #2
    Senior Member
    Dec 2008
    I'm not sure if I'm correct, but after several mistakes I derived an answer for the width of the plank slightly different from 8.5\,\mbox{in}. I used the equations

    \begin{aligned}<br />
y&=\sqrt{100-x^2}-\sqrt{10}\\<br />
A&=2xy=2x(\sqrt{100-x^2}-\sqrt{10}).<br />

    Differentiating, I obtained

    \begin{aligned}<br />
A'&=2\sqrt{100-x^2}+2x\cdot\frac{1}{2}(100-x^2)^{-\frac{1}{2}}\cdot(-2x)-2\sqrt{10}\\<br />
&=2\sqrt{100-x^2}-2x^2(100-x^2)^{-\frac{1}{2}}-2\sqrt{10}=0\quad\mbox{at max}.<br />

    Adding 2\sqrt{10}, multiplying both sides by \sqrt{100-x^2}, and squaring gives us a quadratic equation from which I derived my final answer.
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