Deriving 4x^3 + ln y^2 + 2y = 2x

I think the first step is; 12x^2 + 1 / y^2 + and here is where I'm stuck. What is the derivative of the 2y and 2x?

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- Dec 5th 2009, 07:08 PMArchduke01Logarithmic function
Deriving 4x^3 + ln y^2 + 2y = 2x

I think the first step is; 12x^2 + 1 / y^2 + and here is where I'm stuck. What is the derivative of the 2y and 2x? - Dec 5th 2009, 07:13 PMadkinsjr
- Dec 5th 2009, 07:16 PMArchduke01
- Dec 5th 2009, 08:04 PMArchduke01