The integral of $\displaystyle x^3/\sqrt(1+x)$
How do you start this integral since it is an improper fraction. I tried squaring the top and bottom, but that didn't seem to work. What else should I try
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The integral of $\displaystyle x^3/\sqrt(1+x)$
How do you start this integral since it is an improper fraction. I tried squaring the top and bottom, but that didn't seem to work. What else should I try
correction $\displaystyle x^3/\sqrt(1+x^2)$
so would you then have to figure out
du=$\displaystyle x/\sqrt(1+x^2)$dx or is that not the next step