y = log 10 (x^2 + 6x)
I'm confused how to proceed here. Can anyone provide a step by step solution?
The log is to that base 10 correct?
I'll assume that you know $\displaystyle \frac{d}{du}ln(u)=\frac{1}{u}$
$\displaystyle log_{10}(x^2+6x)=\frac{ln(x^2+6x)}{ln(10)}$
Since $\displaystyle ln(10)$ is a constant, the derivative is
$\displaystyle \frac{1}{ln(10)}\frac{d}{dx}ln(x^2+6x)$
Use the chain rule to obtain:
$\displaystyle =\frac{2x+6}{ln(10)(x^2+6x)}$