y = ln [(e^x + e^-x) / 2] We need to find the derivative of this.
So I extract the 1/2 so it becomes
y = 1/2 ln (e^x + e^-x)
I'm not sure how the chain rule is applied here. The final answer is; (e^x - e^-x) / (e^x + e^-x)
y = ln [(e^x + e^-x) / 2] We need to find the derivative of this.
So I extract the 1/2 so it becomes
y = 1/2 ln (e^x + e^-x)
I'm not sure how the chain rule is applied here. The final answer is; (e^x - e^-x) / (e^x + e^-x)