Results 1 to 3 of 3

Thread: question about mean value

  1. Dec 5th 2009, 02:06 PM #1
    dangerous1
    dangerous1 is offline
    Newbie
    Joined
    Dec 2009
    Posts
    8

    question about mean value

    f(x) = x^3 - 5x^2 - 3x
    find the mean value theorem to find all numbers c in the interval (1,3)

    i got the answer 5 +- (sqrt 16) / 3
    am i correct
    Follow Math Help Forum on Facebook and Google+
  2. Dec 5th 2009, 03:39 PM #2
    tonio
    tonio is offline
    Banned
    Joined
    Oct 2009
    Posts
    4,261
    Thanks
    2
    Quote Originally Posted by dangerous1 View Post
    f(x) = x^3 - 5x^2 - 3x
    find the mean value theorem to find all numbers c in the interval (1,3)

    i got the answer 5 +- (sqrt 16) / 3
    am i correct

    What is "all numbers c in the interval (1,3)"??
    And no, you cannot be correct, whatever c is, since both numbers 5\pm \frac{\sqrt{16}}{3}=5\pm \frac{4}{3} are not in (1,3)...even if the numbers were \frac{5\pm 4}{3} they still aren't in the interval (1,3).

    Tonio
    Follow Math Help Forum on Facebook and Google+
  3. Dec 5th 2009, 03:40 PM #3
    skeeter
    skeeter is offline
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    15,967
    Thanks
    3588
    Quote Originally Posted by dangerous1 View Post
    f(x) = x^3 - 5x^2 - 3x
    find the mean value theorem to find all numbers c in the interval (1,3)

    i got the answer 5 +- (sqrt 16) / 3
    am i correct
    \frac{f(3) - f(1)}{3-1} = -10

    f'(x) = 3x^2 - 10x - 3 = -10

    3x^2 - 10x + 7 = 0

    factor and finish solving for x.
    Follow Math Help Forum on Facebook and Google+
« Integrate this using partial fraction | Solving the initial value first order differential equation »

Search Tags


/mathhelpforum @mathhelpforum