f(x) = x^3 - 5x^2 - 3x

find the mean value theorem to find all numbers c in the interval (1,3)

i got the answer 5 +- (sqrt 16) / 3

am i correct

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- Dec 5th 2009, 01:06 PMdangerous1question about mean value
f(x) = x^3 - 5x^2 - 3x

find the mean value theorem to find all numbers c in the interval (1,3)

i got the answer 5 +- (sqrt 16) / 3

am i correct - Dec 5th 2009, 02:39 PMtonio

What is "all numbers c in the interval (1,3)"??

And no, you cannot be correct, whatever c is, since both numbers $\displaystyle 5\pm \frac{\sqrt{16}}{3}=5\pm \frac{4}{3}$ are not in (1,3)...even if the numbers were $\displaystyle \frac{5\pm 4}{3}$ they still aren't in the interval (1,3).

Tonio - Dec 5th 2009, 02:40 PMskeeter