$\displaystyle \int_0^1 {\frac{{{x^{\frac{1} {2}}}}} {{{{(1 - x)}^{\frac{1} {2}}}}}dx} $ I am thinking u substitution but I am not sure what to sub in
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Originally Posted by genlovesmusic09 $\displaystyle \int_0^1 {\frac{{{x^{\frac{1} {2}}}}} {{{{(1 - x)}^{\frac{1} {2}}}}}dx} $ I am thinking u substitution but I am not sure what to sub in See here: - Wolfram|Alpha Be sure to click on Show steps.
can't you do a trig sub with arc sin because the bottom is (1-x)^.5
Originally Posted by genlovesmusic09 can't you do a trig sub with arc sin because the bottom is (1-x)^.5 But the derivative of arcsin is $\displaystyle \frac{1}{(1- x^2)^{.5}}$, not $\displaystyle \frac{1}{(1-x)^{.5}}$.
Originally Posted by HallsofIvy But the derivative of arcsin is $\displaystyle \frac{1}{(1- x^2)^{.5}}$, not $\displaystyle \frac{1}{(1-x)^{.5}}$. but if i do a u sub where u=x^.5 then x=u^2 so it would be u/(1-u^2)^.5
Originally Posted by genlovesmusic09 but if i do a u sub where u=x^.5 then x=u^2 so it would be u/(1-u^2)^.5 No it doesn't. Have you considered what dx becomes ....?
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