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Math Help - Help with integral

  1. #1
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    Help with integral

    Can anyone help me find the integral of:

    (cosx)^3 * (sinx)^2

    thanks
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  2. #2
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    Quote Originally Posted by messianic View Post
    Can anyone help me find the integral of:

    (cosx)^3 * (sinx)^2

    thanks
    Note that \cos^3 x = \cos x \cos^2 x = \cos x (1 - \sin^2 x). Substitute this expression and then make the substitution u = \sin x.

    If you need more help, please show all your work and say where you get stuck.
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  3. #3
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    Thanks

    Could you help me with another one?

    How would I find the integral of: sin2x*cosx

    or: sinx *cos2x
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  4. #4
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    Quote Originally Posted by messianic View Post
    Thanks

    Could you help me with another one?

    How would I find the integral of: sin2x*cosx

    or: sinx *cos2x
    \sin (2x) \cos x = 2 \sin x \cos^2 and substitute u = \cos x.

    \sin x \cos (2x) = \sin x (2 \cos^2 x - 1) and substitute u = \cos x.

    Please start a new thread for any further new questions.
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