using chain rule or inverse function rule, how can you prove that sin^-1 x is equal to 1/(sqrt(1-x^2))

Printable View

- Oct 30th 2005, 05:10 AMjonny4407[SOLVED] DERIVATIVE OF sin^-1 x
using chain rule or inverse function rule, how can you prove that sin^-1 x is equal to 1/(sqrt(1-x^2))

- Oct 30th 2005, 06:58 AMJamesonQuote:

Originally Posted by**jonny4407**

$\displaystyle \sin^{-1}(x)=y$

So, taking the sine of both sides gives us that $\displaystyle \sin(y)=x$

Draw a triangle with y as the angle, and make the sine of y equal to x. Differentiate both sides of you equation, and solve for $\displaystyle \frac{dy}{dx}$.

Good luck.