Hi. Can anyone help me with this problem?

Find the area of the regions enclosed by the lines and curves with respect to y.

1. y^2 - 4x = 4 and 4x - y = 16

Thanks.

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- Feb 22nd 2007, 12:27 AMturtleAreas in the plane (Calculus)
Hi. Can anyone help me with this problem?

Find the area of the regions enclosed by the lines and curves with respect to y.

1. y^2 - 4x = 4 and 4x - y = 16

Thanks. - Feb 22nd 2007, 06:11 AMSoroban
Hello, turtle!

Quote:

Find the area of the regions enclosed by the line and curve with respect to y.

. . y² - 4x = 4 .and .4x - y = 16

Code:`5+ *`

| ....*

| *:::::*

| *:::::::::*

| *:::::::::::*

*::::::::::::*

*:|::::::::::*

--*-:+:-:-:-:-*--------------

*:|::::::*

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-4+ *

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The graphs intersect at: y = -4, 5.

Solve each equation for x: . x .= .¼y² - 1, . x .= .¼y + 4

. . . . . . . . . . . . .5

The integral is: .∫ [(¼y + 4) - (¼y² - 1)] dy

. . . . . . . . . . . .-4

- Feb 22nd 2007, 10:16 AMJhevon
Soroban, how did you draw that picture, you didn't sit there and type it did you?

- Feb 22nd 2007, 11:07 AManthmoo
- Feb 22nd 2007, 12:23 PMJhevon
Thanks, I guess I'll try to look it up.