# Areas in the plane (Calculus)

• Feb 21st 2007, 11:27 PM
turtle
Areas in the plane (Calculus)
Hi. Can anyone help me with this problem?

Find the area of the regions enclosed by the lines and curves with respect to y.
1. y^2 - 4x = 4 and 4x - y = 16

Thanks.
• Feb 22nd 2007, 05:11 AM
Soroban
Hello, turtle!

Quote:

Find the area of the regions enclosed by the line and curve with respect to y.
. . y² - 4x = 4 .and .4x - y = 16

Code:

```          5+                      *           |                ....*           |            *:::::*           |      *:::::::::*           |  *:::::::::::*           *::::::::::::*         *:|::::::::::*       --*-:+:-:-:-:-*--------------         *:|::::::*           *::::*         -4+  *           |*    *           *|            *         *  |                    *```

The graphs intersect at: y = -4, 5.

Solve each equation for x: . x .= .¼y² - 1, . x .= .¼y + 4

. . . . . . . . . . . . .5
The integral is: .
[(¼y + 4) - (¼y² - 1)] dy
. . . . . . . . . . . .-4

• Feb 22nd 2007, 09:16 AM
Jhevon
Soroban, how did you draw that picture, you didn't sit there and type it did you?
• Feb 22nd 2007, 10:07 AM
anthmoo
Quote:

Originally Posted by Jhevon
Soroban, how did you draw that picture, you didn't sit there and type it did you?

He has a template (like graph paper) in notepad where....

It's too long too explain and there's a post on here that I forget the title on and can not find which explains everything!
• Feb 22nd 2007, 11:23 AM
Jhevon
Thanks, I guess I'll try to look it up.