It may be as simple as noting on the left you should have 8x^3 + 7I get 8x^3= A(2x+1)^6 + B(x+1)(2x+1)^5 + C(x+1)(2x+1)^4 + D(x+1)(2x+1)^3
If the +7 is missing that will make a difference
(8x^3+7)/((x+1)(2x+1)^3)
I get 8x^3= A(2x+1)^6 + B(x+1)(2x+1)^5 + C(x+1)(2x+1)^4 + D(x+1)(2x+1)^3
i get a=-1 and b,c,d=-1/2
i then integrated each individual fraction and got the wrong answer.. somthing is wrong with my above step. can someone help me to solve it properly and why
any help is very appreciated
the tutor at the library told me to do
A/x+1 + B/2x+1 + C/(2x+1)^2 + D/(2x+1)^3
and then i got the common factor...
its obviously wrong because i got the wrong answer, but if someone can help me with the hard part--ill be able to integrate each seperate fraction (hopefully)