Use the series expansion for sinh(x) to evaluate, correct 4 d.p

a) sinh 0.5

b) sinh 2

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- February 21st 2007, 11:41 PMgracyapproximate through infinite series
Use the series expansion for sinh(x) to evaluate, correct 4 d.p

a) sinh 0.5

b) sinh 2 - February 22nd 2007, 02:47 AMchogo
sinh x = x + (x^3)/6 + (x^5)/120 + (x^7)/5040

put in the values of x into this

0.5 + (0.5^3)/6 + (0.5^5)/120 + (0.5^7)/5040 = 0.5210953

2 + (2^3)/6 + (2^5)/120 + (2^7)/5040 = 3.62539683 - February 22nd 2007, 02:48 AMchogo
to check these are correct type into google

sinh(0.5)

or

sinh(2)

sorry and the formula for the power series of sinh is

sinh(x) = x + (x^3)/ 3! + (x^5)/5! + .... + (x^(2n+1)) / (2n+1)!

the maclaurin series which is a Taylor series expansion of a function about 0