find dy/dx of

y= ln(x^2 + 9)^4

i know you have to use the chain rule but i really need some help. i've got an exam tomorrow and i don't konw how to do this

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- Dec 3rd 2009, 05:30 PMboomersooner1331more help needed
find dy/dx of

y= ln(x^2 + 9)^4

i know you have to use the chain rule but i really need some help. i've got an exam tomorrow and i don't konw how to do this - Dec 3rd 2009, 05:44 PMadkinsjr
- Dec 3rd 2009, 05:45 PMPulock2009you couldnot do this!?
y=ln(x^2+9)^4

=>y=4ln(x^2+9)

=>dy/dx=4.1/(x^2+9).2x(Wink) - Dec 3rd 2009, 05:52 PMboomersooner1331
so because it's a logarithm you don' multiply it by 4, and have 3 as an exponent?

- Dec 3rd 2009, 06:48 PMadkinsjr