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Math Help - integral problem

  1. #1
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    integral problem

    \frac{1}{x^2+1}
    bounds 0 to 4.

    I thought it would be \frac{1}{2x}*ln(x^2+1), because it equals \frac{1}{x^2+1}. But I got \frac{1}{8}ln5=.20 and when I checked the definite integral by calculator it was 1.325. What should the antiderivative be?
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  2. #2
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    Oops. Just realized it should be arctan.
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